When 5 V potential difference is applied across a wire of length 0.1 m, the drift speed of electrons is `2.5 xx 10^(-4) ms ^(-1)`. If the electron density in the wire is ` 8 xx 10^(28) m^(-3)`, the resistivity of the material is close to :

Options

A. `1.6 xx 10^(-8) Omega m`
B. `1.6 xx 10^(-7) Omega m`
C. `1.6 xx 10^(-6) Omega m`
D. `1.6 xx 10^(-5) Omega m`

Answer

d

Explanation

According to Ohm's law
`V = IR = 1rho(l)/(A)`
or `rho = (VA)/(Il)`
Now as `1 = A n ev_(d)or rho = (VA)/(l A n e u_(d)) = (V)/(l n e v_(d))`
`p = (5)/(0.1 xx 8 xx 10^(28) xx(1.6 xx10^(-19)) xx 25 xx 10^(-4))`
`= 1.6 xx 10^(-6) Omega m`