In the circuit `AB` is a long wire of `300 Omega` it is tapped at one third distance and is connected as shown The equivalent resistance between A and B is

Options

A. `60 Omega`
B. `32 Omega`
C. `20 Omega`
D. None of above

Answer

B

Explanation

`R_(EF) = (100 xx 25)/(100 + 25) = 20 Omega ,`
`R_(DF) = (120 xx 120)/(120 + 120) = 60 Omega`
`R_(AB) = R_(CF) (160 xx 40)/(160 + 40) = 32 Omega`