In the given circuit digram when the current reaclies steady state in the circuit , the charge an the capacity of capacitance `C` will be

Options

A. `CE(r_(2))/((r + r_(2))`
B. `CE(r_(1))/((r_(1) + r)`
C. `CE`
D. `CE(r_(1))/((r_(2) + r)`

Answer

a

Explanation

At steady state no current flow through capacitor `C`. Thus the current through the network will be Then

`I = (E )/(r + r_(2))` Potential different across `P` and `Q`
`V_(S) - V_(P) = I r_(2)`
Charge on the capactior
`Q = C(V_(S) -V_(P)) = C 1 r_(2) = C xx(E )/((r+r_(2))) r_(2) = (CE r_(2))/(r+ r_(2))`