The resistance between the terminal point A and B of the given infinitely long circuit will be

Options

A. `(sqrt(3) - 1)`
B. `(1 - sqrt(3))`
C. `(1 + sqrt(3))`
D. `(2 + sqrt(3))`

Answer

c

Explanation

Ler `x` the equivalent resistance of infinite net work .Since the net work is infinite , the addition of one more unit of there terminals will not alter , the total resistance each the total resistance of network i.e. it appear alter, the total resistance of network, i.e., it should ne x. Therefore, the network would appear and in total resistance should remain `x` Effective resistance `A` and `B` is

`x = 1 + (1 xx x)/(1 + x) + 1= 2+ (x)/(1 + x)`
On siolving we get `x = (1 + sqrt(3)) Omega `