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A student measure the terminal potential...

A student measure the terminal potential difference `(V)` of a cell (of `emf` internal energy is connected in providing the circuit is

A

`-r and epsilon`

B

`r and -epsilon`

C

` -epsilon and r`

D

` epsilon and -r`

Text Solution

Verified by Experts

The correct Answer is:
a
Terminal pot diff. `V= epsilon - 1 r= - 1 r + epsilon`…..(i)
It shown as `I` increase `V` decrease
The variation of `V` and `I` will be a straight line with negative slope

Comparing (i) with , `y = mx + c`, we have
`:.` slope, `m = -r`, intercept `c = epsilon`
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Knowledge Check

  • A student measures the terminal potential difference (V) of cell (of emf epsi and internal resistance r) as a functionn of the current (l) following through it . The slope and intercept , of the graph between V and l then respectively, equal .

    A
    `-r and epsi`
    B
    ` r and - epsi`
    C
    `-epsi and r `
    D
    `epsi and - r`

  • A student measures the terminal potential difference (V) of a cell (of emf epsilon and internal resistance r ) as a function of the current (I) flowing through it. The slope and intercept of the graph between V and I , then respectively, equal

    A
    `epsilon` and `-r`
    B
    `-r` and `epsilon`
    C
    `r` and `- epsilon`
    D
    `- epsilon` and `r`

  • The terminal potential difference of a cell is greater than its emf when it is

    A
    being discharged
    B
    being charged
    C
    in open circuit
    D
    short circuited

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