Cell having an `emf epsilon ` internal resistance `r` is connected a variable external resistance `R` As the resistance `R` is increased the piot of potential difference `V` across `R` is given by

Options

A.
B.
C.
D.

Answer

c

Explanation

Refer to currect in the circuit
`1 = (epsilon)/(R+r)`

Pot diff across `R`
`V = IR = ((epsilon)/(R+r))R = (epsilon)/(1+r//R)`
When `R = 0, V = 0` , where `R = oo,V= epsilon`
Thus option (c) is true