In the circuit shown, the currect in the `1 Omega` resistor

Options

A. `1.3A` from P to Q
B. `0A`
C. `0.13 A` from Q to P
D. `0.13 A` from P to Q

Answer

c

Explanation

The circuit can be redrawn as

In closed loop `RPQSR`
`2I_(1) + 1(I_(1) - I_(2)) +3 I_(1) = 9`
`3I_(1) - I_(2)= 9`
In closed loop `PUTQOP`
`3I_(2) - 1(I_(1) - I_(2)) = 6`
`-I_(1) - 4I_(2)= 6`
From (i) and (ii),
`I_(1) - I_(2)= -0.13A`
This current is `0.13 A` from Q to P