In the circuit shown in fig the heat produced in the 5 ohm resistor due to the current flowing through it is 10 calories per second.

The heat generated in the 4 ohms resistor is

Options

A. 1 calorie/sec
B. 2 calorie//sec
C. 3 calorie//sec
D. 4 calorie//sec

Answer

c

Explanation

Given heat produced per second in `5 Omega`
`= 10 "calories"//s = 10 xx 4.2 Js^(-1)`
`V^(2)//5 = 10 xx 4.2 or V = sqrt(42 xx 5)` volt
pot diff across A and B `= sqrt(42 xx 5)` volt
Current in `6 Omega, I = sqrt(42 xx 5)/(10)` ampere
Heat potential per second in `6 Omega`
`= (sqrt(42 xx 5)/(10))^(2) xx 61 s^(-1)`
`= (42xx 5)//(100) xx (6)/(4.2) "calories/second" = 3 "cal/s"`