A 100 W bulb `B_(1)` and two 60 W bulbs `B_(2)` and `B_(3)`, are connected to a 250V source, as shown in the figure now `W_(1),W_(2)` and `W_(3)` are the output powers of the bulbs `B_(1),B_(2)` and `B_(3)` respectively then

Options

A. `W_(1) gt W_(2) = W_(3)`
B. `W_(1) gt W_(2) gt W_(3)`
C. `W_(1) lt W_(2) = W_(3)`
D. `W_(1) lt W_(2) lt W_(3)`

Answer

d

Explanation

Voltage across `B_(3)` is greatest, hence `B_(3)` will show maximum brightness. In series combination of bulbs the bulb of lesser wattage will glow more bright Hence `W_(2) gt W_(1)` so `W_(1) lt W_(2) lt W_(3)`