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The charge flowing in a conductor varies...

The charge flowing in a conductor varies with times as `Q = at - bt^2.` Then, the current

A

decrease linealy current

B

reaches maximum and then decrease

C

falls to zero after `t = a//2b`

D

changes at a cate of `- 2b`

Text Solution

Verified by Experts

The correct Answer is:
a,c,d

(a) `I = (dQ)/(dt) = (d)/(dt) (at - bt^(2)) = a- 2bt`
i.e., `I` decreases with time
(c) For `I = 0,a- 2bt = 0 or t = a//2b`
(d) Rate of change of current
`(dI)/(dt) = (d)/(dt) ( a- 2bt) = -2b`
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