For the circuit

Options

A. potential difference between points `B and E` is `5V`
B. potential difference between points `B and B` is `10V`
C. the current in the `4 CE arm` resistor is `0.25 A`
D. the current in the ` BE arm` resistor is `0.5 A`

Answer

a,c,d

Explanation

The resistances `2 Omega ` and `2 Omega ` in series of arms of `CDE` ares in parallel to resistance `4 Omega` in arm `CE` Their effective resistance `= (4 xx (2+2))/(4 + (2+2)) = 2 Omega`. This resistance is in series with `8 Omega` of arm BC. The effective resistance is `8 + 2 = 10 Omega ` which is in parallel across `10 Omega` resistance of arm `BE` The effective resistance `B` and `E`
`R = (10 xx 10) /(10+ 10) = 5 Omega `
Total resistance of circuit , `I = 5+ 5 + 15 = 25 Omega`
Current in circuit, `I = (25 V)/(25 Omega) = 1A`
Potential difference across `B` and `E = IR = 1xx 5 = 5V`
Potential difference across `A` and `B = 25 - 5 = 20V`
Current in arm `BE,I_(1)= (5)/(10) = (1)/(2) A`
Current in arm `BC` is also `I_(1)(= (1)/(2)A)`
Current in arm `CE = ` Current in arm `CDE`
`= (1)/(4) A = 0.25 A`