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For the circuit...

For the circuit

A

Equivalent internal resistance `R` is given by
`(1)/(R ) = (1)/(R_(1)) + (1)/(R_(2)) + (1)/(R_(3))`

B

Equivalent emf of the bettery in
`E = (E_(1) + E_(2) +E_(3)) //3`

C

If `E_(1)= ((E_(1)R_(1) + E_(2)R_(2))/(R_(1) +R_(2)))` equivqalent e.m.f. of the battery will be equal to `E_(3)`

D

Equivalent emf of the battery in
not only depent upon value of `E_(1),E_(2) and E_(3)` but depends upon value of `R_(1),R_(2) and R_(3)` also

Text Solution

Verified by Experts

The correct Answer is:
a,c,d

As cell are to parallel the equivalent internal resistance `R` is `(1)/(R) = (1)/(R_(1)) + (1)/(R_(2)) = (1)/(R_(3))`
On appliying kirchhoff's voltage law in the loops
we can get `E_(1) = (E_(1) R_(2) +E_(2)R_(1))/(R_(1) + R_(2))`
Equivalent emf of the battery depends upon the value of `E_(1), E_(2), E_(3)` and also on `R_(1) R_(2) and R_(3)`
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