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Five identical lamps , each of resistanc...

Five identical lamps , each of resistance `1100 Omega` are connected to `220 V` The reading of an ideal ammeter `A` is

A

`(220)/(1100)xx 1A`

B

`(220)/(1100)xx 2A`

C

`(220)/(1100)xx 3A`

D

`(220)/(1100)xx 5A`

Text Solution

Verified by Experts

The correct Answer is:
c
In the given circuit the potential difference across each resistor is `220V` The currect through ammeter in the sum of currect flowing through the three resistance to parallel to the right of ammeter
`:.` Current through ammeter `= 3 xx(220)/(11000)A`
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