If `2 xx 10^(20)` electrons pass through a loop in one minute, What is the current in milliampere ?

Answer

`533 mA`

Explanation

Here , `n = 2 xx 10^(20), t = 60 s`
`I = (n e)/(t) = ((2 xx 10^(20))xx (1.6xx 10^(-19)))/(60)`
`= 0.533 A = 533 mA`