If `0.6` mole of electrons through a wire in `50` minutes What is (a) the total charge the passes drough the wire and (b) the magnitude of the current ? Avarege a number `= 6 xx 10^(23)` per mol

Answer

(a)` 5.76 xx 10^(6)C(b)`19.2 A`

Explanation

(a) No of elecrons in 0.6 mol,
`N = 0.6 xx (6 xx 10^(23))`
Charge flowing
`q = Ne = 0.6 xx 6xx 10^(23)xx (1.6 xx 10^(-19))C`
`= 5.76 xx 10^(6)C`
(b) Current `I = (q)/(t)= (5.76 xx 10^(6))/(50 xx 60) = 19.2 A`