What is the drift velocity of electrons in a silver wire of length `1m` having cross-section area `3.14 xx 10^(-6)m^(2)` and carriying a current of `10A`. Given atoms weight of weight of silver `= 108` density of silver `10.5 xx 10^(3) kg//m^(3)`, charge of electron `1.6 xx 10^(-19) C`, Avogadro's number `6.023 xx 10^(26)` per kg.atom

Answer

`3.4 xx 10^(-4)ms^(-1)`

Explanation

No of electron per unit volume of silver,
`n = (N)/(M//d) = (Nd)/(M)`
`= (6.023 xx 10^(26))/(108) xx (10.5 xx 10^(3)) = 5.8557 xx 10^(28)`
Then `upsilon_(d) = (I)/(nAe)`
`=(10)/(5.8557 xx 10^(28) xx 3.14 xx 10^(-6) xx 1.6 xx10^(-19))`
`= 3.4 xx 10^(-4)ms^(-1)`