Calculate the resistivity of the material of a wire 1.0 m long, 0.4 mm diameter and having a resistance of `2.0 Omega`.

Answer

` 2.53 xx 10^(-6) Omega m`

Explanation

`rho = (RA)/(l) = (R pi D^(2))/(4l) = (2.0 xx 3.142 xx (0.4 xx 10^(-3))^(2))/( 4xx 10)`
`= 2.51 xx 10^(-8) Omega m`