What is the equivalent resistance between `A and H` of resistances

Answer

`10 Omega`

Explanation

Here, `i_(3) = 2 - (0.8 + 0.4) = 0.8 A`
Potential difference across `D and E`
`= 10 xx i_(3) = 10 xx 0.8 = 8 V`
Potential difference across `B and G` = potential difference across `C and F` potential difference across D and E
`:. 0.8 R_(3) = 0.4 R_(2) = 8`
or `R_(3) = (8)/(0.8) = 10 Omega and R_(2) = (8)/(0.4) = 20 Omega`
Equivalent resistance between B and G,R' is given
`(1)/(R') = (1)/(10) + (1)/(20) + (1)/(10) + (5)/(20) = (1)/(4) orR' = 4 Omega`
Total resistance `A and H`
`= 6 + 4 = 10 Omega`