Calculate the energy stored in the condenser the given circuit

Answer

`4 xx 10^(-4)J`

Explanation

Total resistance of arm `ABCD`
`R = 2+ 3 + 5 = 10 Omega`
Potential difference across `A and D`
`V = 1 xx R = 2 xx 10 = 20V`
Energy stored in capctor `= (1)/(2) CV^(2)`
`= (1)/(2) xx (2 xx 10^(-6)) xx (20)^(2) = 4 xx 10^(-4)J`