Apply kirchhoff's rules to the length `PRSP` and `PRQP` to wire the expression for the current `I_(1), I_(2) and I_(3)` in the circuit

Answer

`(39)/(860)A ; l_(2) = (4)/(215) A ; l_(3) = (11)/(172) A`

Explanation

By kirchhoff's first rate
`l_(3) = l_(1) + l_(2)`….(i) According to kirchhoff's second rate
For loop PRSP `20 l_(3) + 200 l_(2) = 5`……(ii)
For loop `PRQP 20 l_(3) + 60 l_(1) = 4`……(iii)
solving (i),(ii) and (iii) we get
`l_(1) = (39)/(860)A , l_(2) = (4)/(215) A , l_(3) = (11)/(172) A`