Find the current `I_(1) ,I_(2) and I_(3)` through the there resistor circuit

Answer

0

Explanation

According to kirchhoff's loop rate
For the loop `ABGHA 5l_(1) = - 2+ 2 = 0 or l_(1) = 0 `
For loop `BCFGB 5l_(2) - 5l_(1) = - 2 + 2 = 0`
or `5l_(2) = 5l_(1) = 5 xx 0 = 0 or l_(2) = 0`
For loop `5l_(3) - 5l_(2) = - 2 + 2 = 0`
`5l_(3) = 5l_(2) = 5 xx 0 or l_(3) = 0 `