`P,Q R and S` four resistance wires of resistance `1,2,3 and 4` ohm respectivily. They are connected in form the four arms of Wheatstone bridge circuit. Find out the resistance with which `S` meat be shunted in order the bridge may be balanced
Text Solution
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The correct Answer is:
`12 Omega `
For balance wheastone bridge `(P)/(Q) =(R )/(S) ` Here `P = 3 Omega Q = 3 Omega , R = 3 Omega ` `:. (3)/(3) = (3)/(S) or S = 3 Omega ` Therefore the resistance of `4 Omega ` must be shunted with a resistance `x` so that the conbination resistance of `4 Omega` and `x` is equal to `3 Omega ` so `(1)/(x )+(1)/(4) + (1)/(3) or (1)/(x) = (1)/(4) - (1)/(12) or x = 12 Omega `
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