A motor operating on `120 V` draws a current of `2 A` . If the heat is developed in the motor at the rate of `9 cal s^(-1)`, what is the efficiency?

Answer

`80.9%`

Explanation

Here`V= 110 V, l = 2A`
power supplied to motor `= 1//1 = 110 xx 2 = 220 W`
power loss in the form of heat `= 10 cals^(-1)`
`= 10 xx 4.2 Js^(-1) = 42 Js^(-1)`
power used by motor `= 220 - 42 = 178 W`
Effeciency `eta = ("power used by motor")/("power supplied to motor") xx 100`
`= (178)/(220) xx 100 = 80.9%`