A house is fitted with `20` length of `60` watt each `10` fans consuming `0.5` ampere each an electric kettle of resistance `110 Omega`. If the energy is supplied at `120 V` and costs `150` paise `kWh`, calculate monthly bill for running these appliances for 6 hours a day (1 length = 30 days).

Answer

`739.80 Rs`

Explanation

Total energy connected in a all appliance ltnrgt `= (n_(1)P_(1) + n_(2)//V = (V^(2))/(R )) t xx 30`
`= ( 20 xx 600 + 10 xx 0.5 xx 220 + (220^(2))/(110)) xx 6 xx 30`
`= (1200 + 1100 + 440 xx 6 xx 30 `watt hour
`= (2740 xx 6 xx 30)/(1000) kWh`
Cost of electricity consumption
`= (1.50 xx 2740 xx 6 xx 30)/(1000) = 739.80 Rs`