A cell sends a current through a resistance `R_(1)` for time `t`, next the same cell sends current through another resistance `R_(2)` for the time `t` If the same amount of heat is developed in both the resistance then find the internal resistance of the cell

Answer

`sqrt(R_(1)R_(2))`

Explanation

As per question ,`(epsilo^(2)R_(1))/((R_(1) + r)^(2)) = (epsilo^(2)R_(2))/((R_(2) + r)^(2))`
solve it for `r` in terms `R_(1) and R_(2)` we shall get
`r = sqrt(R_(1)R_(2))`