In the circuit shown in fig the heat produced in the 5 ohm resistor due to the current flowing through it is 10 calories per second.

The heat generated in the 4 ohms resistor is

Answer

`80 cal`

Explanation

Let `l, l_(1) ` be the current through upper and lower area of the circuit .resistance of upper arm of circuit `= 2 + 3 = 5 Omega`
resistance of lower arm `= 6 + 4 = 10 Omega`
Heat prodeced in `4 Omega` resistance
`= l_(1)^(2) xx 4 =40 xx 4.2 J`
`or l_(1)^(2) = 10 xx 4.2 or l_(1) sqrt(42)A`
pot diff across lower arm
`= l_(1) xx 10 = sqrt(42) xx 10 V`
pot diff across arm `= 10 sqrt(42) V`
Cyrrent through upper arm
`l = 10 sqrt(42)//5 = 2 sqrt(42)A`
Here produced per second in `2 Omega` resistance
`= ((2 sqrt(42))^(2) xx 2 xx 1)/(4.2) = 80 cal`