Home
Class 11
MATHS
The area bounded by the curves y = sqrt(...

The area bounded by the curves `y = sqrt(x)` ; `2y+3 = x` and `x-` axis in the 4th quadrant is

Text Solution

AI Generated Solution

To find the area bounded by the curves \(y = \sqrt{x}\), \(2y + 3 = x\), and the x-axis in the 4th quadrant, we will follow these steps: ### Step 1: Find the intersection points of the curves We need to find where the curves \(y = \sqrt{x}\) and \(2y + 3 = x\) intersect. 1. Substitute \(y = \sqrt{x}\) into the equation \(2y + 3 = x\): \[ 2\sqrt{x} + 3 = x ...
Promotional Banner

Topper's Solved these Questions

  • RELATIONS AND FUNCTIONS

    NCERT|Exercise EXERCISE 2.1|10 Videos
  • RELATIONS AND FUNCTIONS

    NCERT|Exercise SOLVED EXAMPLES|22 Videos
  • PROBABILITY

    NCERT|Exercise EXERCISE 16.3|21 Videos
  • SEQUENCES AND SERIES

    NCERT|Exercise EXERCISE 9.5|6 Videos

Similar Questions

Explore conceptually related problems

Find the area bounded by the curves y=sqrt(x),2y+3=x and x -axis.

The area bounded by the curves y=sqrt(x),2y-x+3=0, X-axis and lying in the first quadrant is

Find the area of the region bounded by the curves x^2 +y^2 =4, y = sqrt(3) x and x- axis in the first quadrant

The area bounded by the curve y = sin2x, axis and y=1, is

The area bounded by the curves y^(2)=x^(3) and |y|=2x

The area bounded by the curves y=2-|2-x| and |x|y=3 is

Find the area of the region bounded by the curves x^(2)+y^(2)=4 , y=sqrt(3)x and x -axis in the first quadrant.