`CH_(3)-underset(Cl-C-Br)underset(||)C-Cl` is

Options

A. trans
B. `Z`
C. both correct
D. none of these

Explanation

To determine the configuration of the compound `CH₃-CH(Cl)-CH(Br)-C(Cl)`, we need to analyze the substituents on the double bond and apply the Cahn-Ingold-Prelog priority rules. Here’s a step-by-step solution:

### Step 1: Identify the Double Bond
The compound has a double bond between two carbon atoms. We need to identify the two carbon atoms involved in the double bond and their substituents.

### Step 2: Assign Priorities to Substituents
For the two carbon atoms involved in the double bond, we will assign priorities to their substituents based on atomic number:
- For the first carbon (C1) attached to the double bond:
- CH₃ (methyl group) has a lower priority (atomic number 6 for carbon) compared to Cl (atomic number 17).
- Therefore, Cl has a higher priority than CH₃.

- For the second carbon (C2) attached to the double bond:
- Cl has a higher priority than Br (atomic number 35) since both are halogens.
- Therefore, Br has a lower priority than Cl.

### Step 3: Determine the Configuration
Now we have:
- C1: Cl (higher priority) and CH₃ (lower priority)
- C2: Cl (higher priority) and Br (lower priority)

Now we can analyze the arrangement:
- If the higher priority groups (Cl on C1 and Cl on C2) are on the same side of the double bond, it is a Z configuration.
- If they are on opposite sides, it is an E configuration.

In our case, since both Cl groups are on the same side, the configuration is Z.

### Step 4: Conclusion
Thus, the compound `CH₃-CH(Cl)-CH(Br)-C(Cl)` is in the Z configuration.

### Final Answer
The compound is in the Z configuration.

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