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A system consists of a thin symmetrical ...

A system consists of a thin symmetrical converging glass lens with the curvature radius of its surfcaes `R = 38 cm` and a plane mirror oriented at right angles to the optical axis of the lens. What is the optical power of this system when the space between the lens and the mirror is filed up with water ?

Text Solution

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The plane mirror forms the image of the lens, and water, filled in the space between the two, behind the mirror, as shown in the figure.
So, the whole optical system is equivalent to two similar lenses, seperated by a distance `2l` and thus, the power of this system,
`Phi = Phi_(1) + Phi_(2) - (dPhi_(1)Phi_(2))/(n_(0))`, where `Phi_(1) = Phi_(2) = Phi'_(1)`
`=` optical power of individual lens and `n_(0) = R.I.` of water.
Now, `Phi' =` optical power of first convex surface `+` optical power of second concave surface.
`= ((n - 1))/(R ) + (n_(0) - n)/(R ), n` is the refractive index of glass.
`((2n - n_(0)1))/(R) ...........(1)`
and so, the optical of whole system
`Phi = 2Phi' - (2d Phi'^(2))/(n_(0)) = 3.0 D`, substituting the values.
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