The temperature of one of the two heated black bodies is `T_(1) = 2500K`. Find the temperature of the other body if the wavelength corresponding to its maximum emissive capacity exceeds by `Delta lambda = 0.50mu m` the wavelength corresponding to the maximum emissive capacity of the first black body.

Explanation

For the first black body
`(lambda_(min))_(1) = (b)/(T_(1))`
Then `(lambda_(min))_(2) = (b)/(T_(1)) + Delta lambda = (b)/(T_(2))`
Hence `T_(2) = (b)/((b)/(T_(1))+Delta lambda) = (bT_(1))/(b+T_(1)Delta lambda) = 1.747kK`