What hydrogen-like ion has the wavelength difference between the first lines of the Balmer Lyman series equal to `59.3nm`?

Explanation

From the formula of the previous problem
`Delta lambda=(176 pi c)/(15 Z^(2)R)`
or `Z=sqrt((176pi c)/(15R Delta lambda))`
Substitution of `Delta lambda = 59.3nm` and `R` and the previous gives `Z=3` This identifies the ion as `Li^(++)`