Given mass of the moon is 1/81 of the ma...

Given mass of the moon is 1/81 of the mass of the earth and corresponding radius is 1/4 of the earth. If escape velocity on the earth surface is 11.2 km / s , the value of same on the surface of the moon is

0.14 km/s

0.5 km/s

2.5 km/s

5 km/s

Text Solution

Verified by Experts

The correct Answer is:

On earth `v_e=sqrt((2GM)/R)` =11.2 km/s
On moon `v_m=sqrt((2GMxx4)/(81xxR))=2/9sqrt((2GM)/R)`
`=2/9xx11.2` =2.5 km/s

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