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The time period of a simple pendulum in ...

The time period of a simple pendulum in a lift descending with constant acceleration g is

A

`T=2pisqrt(I/g)`

B

`T=2pisqrt(I/(2g))`

C

Zero

D

Infinite

Text Solution

Verified by Experts

The correct Answer is:
D
This is the case of freely falling lift and in free fall of lift effective g for pendulum will be zero.
So `T=2pisqrt(l/0)=oo`
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