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A weight of 200 kg is suspended by verti...

A weight of 200 kg is suspended by vertical wire of length `600.5 cm`. The area of cross-section of wire is `1mm^(2)`. When the load is removed, the wire contracts by `0.5 cm`. The Young's modulus of the material of wire will be

A

`2.35xx10^12 N//m^2`

B

`1.35xx10^10 N//m^2`

C

`13.5xx10^11 N//m^2`

D

`23.5 xx 10^9 N//m^2`

Text Solution

Verified by Experts

The correct Answer is:
A
F=2000 N , L=6m , I=0.5 cm , `A=10^(-6) m^2`
`Y=(FL)/(Al)=(2000xx6)/(10^(-6)xx0.5xx10^(-2)) = 2.35xx10^12 "N/m"^2`
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