In figure `S_(1)` and`S_(1)` are identical springs. The oscillation frequency of the mass `m` is `f`. if one spring is removed, the frequency will become

Options

A. f
B. f x 2
C. `f xx sqrt2`
D. `f//sqrt2`

Answer

D

Explanation

For the given figure `t=1/(2pi) sqrt((k_"eq")/m) = 1/(2pi)sqrt((2k)/m)` …. (i)
If one spring is removed , then `k_"eq" = k` and `f'=1/(2pi) sqrt(k/m)` …(ii)
From equation (i) and (ii) , `f/(f')=sqrt2 rArr f'=1/sqrt2`