The radius of a soap bubble is increased...

The radius of a soap bubble is increased from `(1)/(sqrtpi)` cm to `(2)/(sqrtpi)` cm. If the surface tension of water is `30"dynes"` per cm, then the work done will be

A

180 ergs

B

360 ergs

C

720 ergs

D

960 ergs

Text Solution

Verified by Experts

The correct Answer is:

C

`W=8piT(r_2^2-r_1^2) = 8piT[(2/sqrtpi)^2 - (1/pi)^2]`
`therefore W=8xxpixx 30xx3/pi` = 720 erg

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