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One mole of helium is adiabatically expa...

One mole of helium is adiabatically expanded from its initial state `(P_(i),V_(i),T_(i))` to its final state `(P_(f),V_(f),T_(f))`. The decrease in the internal energy associated with this expansion is equal to

A

`C_V(T_i-T_f)`

B

`C_P(T_i-T_f)`

C

`1/2(C_P+C_V)(T_i-T_f)`

D

`(C_P-C_V)(T_i -T_f)`

Text Solution

Verified by Experts

The correct Answer is:
A
`DeltaU=muC_VDeltaT=1xx C_V(T_f-T_i) = -C_V (T_i -T_f)`
`rArr |DeltaU|=C_V(T_i-T_f)`
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