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A 0.10 kg block oscillates back and fort...

A 0.10 kg block oscillates back and forth along a horizontal surface. Its displacement from the origin is given by: `x = (10 cm) cos [ (10 rads)t + pi//2 rad]` what is the maximum accelration experiends by the block

A

`10 "m/s"^2`

B

`10 pi "m/s"^2`

C

`(10pi)/2 "m/s"^2`

D

`(10pi)/3 "m/s"^2`

Text Solution

Verified by Experts

The correct Answer is:
A
`a=10xx10^(-2)` m and `omega`=10 rad/sec
`A_"max"=omega^2a = 10xx10^(-2) xx 10^2 =10"m/sec"^2`
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