The flux linked with a circuit is given by `phi=t^(3)+3t-7` . The graph between time (`x`-axis) and induced emf (`y`-axis) will be

Options

A. straight line through the origin
B. straight line with positive intercept
C. straight line with negative intercept
D. parabola not through the origin

Answer

D

Explanation

`phi=t3+3t-7`
`e=-(dphi)/"dt"=-(3t^2 +3)`
e v/s graph : y = – 3x2 – 3, this is parabola, not through origin.