In a transistor, the current amplificati...

In a transistor, the current amplification factor `alpha` is 0.9. The transistor is connected in common base configuration. The change in collector current when base current changes by 4 mA is

1.2 mA

12 mA

24 mA

36 mA

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The correct Answer is:

`beta=alpha/(1-alpha)=0.9/(1-0.9)=9`
`I_C=betaI_B =9xx4` mA = 36 mA

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