If the current through a solenoid changes with time electromagnetic induction takes place in the solenoid. This is known as self-induction. In general, for a current I, the induced emf in the coil is `e=-L(dI)/(dt)`.
L is the self-inductance of the solenoid. On the other hand, such change in the current in a solenoid can produce electromagnetic induction in another adjacent solenoid. The induced emf in the other solenoid `e=-M(dI)/(dt)`, M is called the mutual inductance of the solenoids.
If `L_(1)` and `L_(2)` are the self-inductance of the adjacent coils then their mutual inductance `M=ksqrt(L_(1)L_(2))`. If the magnetic flux produced by the current in one coil is totally linked with the other coil then k = 1.
The self-inductance (in H) of a coil when the induced emf is `50muV` for a change of 1 mA.`s^(-1)` in current through it, is

Options

A. 50
B. 5
C. 0.5
D. 0.05

Answer

D