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The current through a coil of self-induc...

The current through a coil of self-inductance 500 mH is 4 A. What amount of magnetic energy (in J) is stored in its magnetic field?

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4
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The current through a coil of self inductance L = 2mH is given by I=t^(2)e^(-t) at time t. How long it will take to make the e.m.f zero?

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Knowledge Check

  • A fully charged capacitor C with initial charge q_0 is connected to a coil of self-inductance L at t=0. The time at which the energy is stored equally between the electric and the magnetic field is

    A
    `pi/4sqrt(LC)`
    B
    `2pisqrt(LC)`
    C
    `sqrt(LC)`
    D
    `pisqrt(LC)`

  • If current I passes through a pure inductor of self-inductance L, the energy stored is

    A
    `LI^(2)`
    B
    `(LI^(2))/(2)`
    C
    `(LI^(2))/(4)`
    D
    zero

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    Find out the energy stored in a coil of self inductance L due to a current I through it.

    What will be the self-inductance of a solendoid of length 1m, diameter 12cm and number of turns 4000? How much energy will be stored in its magnetic field due to a current of 2A through it? (mu_(0)=4pixx10^(-7)H.m^(-1)) .

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    A straight solenoid of length 50 cm and across sectional area 1cm^(2) has a self-inductance of 10^(-5)H . If a current of 100 mA passes through it, what will be the magnetic field along its axis?

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