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A current flowing through a coil changes...

A current flowing through a coil changes from +2A to -2A in 0.05 s and an emf of 8 V is induced in the coil. The value of self-inductance of the coil is

A

0.8 H

B

0.1 H

C

0.2 H

D

0.4 H

Text Solution

Verified by Experts

The correct Answer is:
B
We know, `e=-L(dI)/(dt)`
or, `L=(-edt)/(dI)=(8xx0.05)/(-2-(+2))=(0.4)/(4)=0.1H`
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