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A metallic disc of radius 10 cm is rotat...

A metallic disc of radius 10 cm is rotating uniformly about a horizontal axis passing through its centre with angular velocity 10 revolution per second. A uniform magnetic field of intensity `10^(-2)T` acts along the axis of the disc. Find the potential difference induced between the centre and the rim of the disc.

Text Solution

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Radius of the metallic disc, R = 10 cm = 0.1 m
Now, magnetic field, `B=10^(-2)T`
Frequency, n = 10
Angular velocity, `omega=10xx2pi" rad."s^(-1)`
`therefore` The value of induced potential difference between the end point and the centre of the metallic disc
`=(1)/(2)BomegaR^(2)=(1)/(2)xx10^(-2)xx10xx2pixx(0.1)^(2)`
`=3.14xx10^(-3)V=3.14mV`
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