The peak value of an alternating magnetic field B is 0.01 T and Frequency is 100 Hz. IF a conducting ring of radius 1 m is held normal to the field , what emf will be induced in the ring?

Explanation

n=100 Hz
`therefore` Time period, `T=1/n=1/100s`
The time taken by the field to increase from 0T to 0.01T is `T/4=1/100s.`
Now area, `A=pi.1^2=pim^2`
Hence induced emf,
`|e|=(dphi)/(dt)=d/(dt)(BA)=A(dB)/(dt)`
or , `|e|=pi((0.01-0)/(1/400))=4piV=12.57 V`