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Mole fraction of C(3)H(5)(OH)(3) in a s...

Mole fraction of ` C_(3)H_(5)(OH)_(3)` in a solution of ` 36 g ` of water and `46 g` of glycerine is :

A

` 0.46 `

B

` 0.36 `

C

` 0.20 `

D

` 0.40 `

Text Solution

Verified by Experts

The correct Answer is:
C
Mole of ` H_(2)O = (36)/(18)=2`
Mol e of glycerine =` (46)/(92) =0.5 `
total Mo le =` 2=0.5 =2.5 `
Mole fraction of glycerine = ` (n_(1))/(n_(1)+n_(2)) =(0.5)/(2.5)X_(0)=0.2 `
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Calculate the mole fraction of C_(3)H_(5)(OH)_(3) in a solution of 36 g of water and 46 g of glycerine.

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