The density of a solution containing `13%` by mass of sulphuric acid is `1.09g//mL`. Calculate the molarity and normality of the solution

Options

A. ` 1.445M `
B. ` 14.45M `
C. ` 144.5M `
D. ` 0.1445M `

Answer

A

Explanation

Volume of ` 100g `of the solution =` (100)/(d)`
`=(100)/(1.09)mL = (100)/(1.09xx1000)` litre
`(1)/(1.09xx10)` litre
Numbers of moles of `H_(2)SO_(4)` in `100 g` of the solution
`=(13)/(98)`
Molarity `= ("No. of moles of water")/("Volume in litre")`
`(13)/(98)xx(1.09xx10)/(1)=10445 M`