Calculate the molality of `1 L` solution of `93% H_(2)SO_(4)` (Weight/volume) The density of the solution is `1.84 g`.

Options

A. ` 9.42 `
B. ` 10.42 `
C. ` 11.42 `
D. ` 12.42 `

Answer

B

Explanation

Given `H_(2)SO_(4)` is `93%`by volume
wt. of `H_(2)SO_(4)`=`93g`
volume of the solution =`100ml`
`:.`Weight of solution=`100ml`
`:.`weight of solution =`100xx1.84gm=184g`
wt. of water =`184-93=91g`
Molarity =`("Moles")/("wt. of water in kg")`
`=(93xx1000)/(98xx91)=10.42`