A solution has ` 25% `of water,` 25% `ethanol and ` 50% `acetic acid by mass. Calculate the mol e fraction of each component.

Options

A. ` 0.50, 0.3, 0.19 `
B. ` 0.19,0.3,0.50 `
C. ` 0.3, 0.19, 0.50 `
D. ` 0.50, 0.19, 0.3 `

Answer

D

Explanation

Since `18`g of water=`1Mol e`
`25g`of water=`(25)/(18)=1.38mol e`
similarly,`46g`of ethanol =`1Mol e`
`25g`of ethanol=`(25)/(46)=0.55mol es`
Again,`60g`of acetic acid =`1mol e`
`50g`of acetic acid=`(50)/(60)=0.83mol es`
`:.`Mole fraction of water=`(1.38)/(1.38+0.55+0.83)=0.50`
similary,mole fraction of ethanol
`=(0.55)/(1.38+0.55+0.83)=0.19`
mole fraction of acetic acid=`(0.83)/(1.38+0.55+0.83)=0.3`