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For an ideal binary liquid solution with...

For an ideal binary liquid solution with `P_(A)^@gtP_(B)^@" "x_(A)`and `y_(A)` represent the mole fraction of A in liquid phase and vapour phase respectively whereas `x_(B)` and `y_(B)` represent the mole fraction of B in liquid phase and vapour phase respectively, therefore which of the following relation is correct?

A

`x_(A)=y_(A)`

B

`x_(A)gty_(A)`

C

`(x_(A))/(x_(B))lt(y_(A))/y_(B)`

D

`(x_(A))/(x_(B))gt(y_(A))/y_(B)`

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The correct Answer is:
To solve the problem regarding the relations in an ideal binary liquid solution, we will use Raoult's Law and the definitions of mole fractions in both the liquid and vapor phases. ### Step-by-Step Solution: 1. **Understanding the Definitions**: - Let \( P_A^0 \) and \( P_B^0 \) be the vapor pressures of pure components A and B, respectively. - Let \( x_A \) and \( x_B \) be the mole fractions of A and B in the liquid phase, respectively. Since it is a binary solution, \( x_A + x_B = 1 \). - Let \( y_A \) and \( y_B \) be the mole fractions of A and B in the vapor phase, respectively. Similarly, \( y_A + y_B = 1 \). 2. **Applying Raoult's Law**: - For component A: \[ P_A = x_A P_A^0 \] - For component B: \[ P_B = x_B P_B^0 \] 3. **Total Pressure of the Solution**: - The total pressure of the solution, \( P_{\text{solution}} \), is the sum of the partial pressures: \[ P_{\text{solution}} = P_A + P_B = x_A P_A^0 + x_B P_B^0 \] 4. **Using the Definitions of Vapor Phase**: - The mole fraction of A in the vapor phase can be expressed as: \[ y_A = \frac{P_A}{P_{\text{solution}}} = \frac{x_A P_A^0}{x_A P_A^0 + x_B P_B^0} \] - Similarly, for component B: \[ y_B = \frac{P_B}{P_{\text{solution}}} = \frac{x_B P_B^0}{x_A P_A^0 + x_B P_B^0} \] 5. **Relating the Mole Fractions**: - From the definitions of \( y_A \) and \( y_B \), we can derive: \[ \frac{y_A}{y_B} = \frac{x_A P_A^0}{x_B P_B^0} \] - Rearranging gives us: \[ \frac{y_A}{y_B} = \frac{x_A}{x_B} \cdot \frac{P_A^0}{P_B^0} \] 6. **Conclusion**: - Therefore, the correct relation that can be established for an ideal binary liquid solution is: \[ \frac{y_A}{y_B} = \frac{x_A}{x_B} \cdot \frac{P_A^0}{P_B^0} \]

To solve the problem regarding the relations in an ideal binary liquid solution, we will use Raoult's Law and the definitions of mole fractions in both the liquid and vapor phases. ### Step-by-Step Solution: 1. **Understanding the Definitions**: - Let \( P_A^0 \) and \( P_B^0 \) be the vapor pressures of pure components A and B, respectively. - Let \( x_A \) and \( x_B \) be the mole fractions of A and B in the liquid phase, respectively. Since it is a binary solution, \( x_A + x_B = 1 \). - Let \( y_A \) and \( y_B \) be the mole fractions of A and B in the vapor phase, respectively. Similarly, \( y_A + y_B = 1 \). ...
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  14. Which liquids pair shows a positive deviation from Raoult's law?

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